TCS NQT Aptitude Test Questions- 15 Questions:
TCS NQT Aptitude
1. One day Shantanu started 30 min late from his house and reached his office 50 min late while walking 25% slower than his general speed. How much time in minutes does Shantanu take to reach his office from home?
- a) 45 minutes.
- b) 50 minutes.
- c) 55 minutes.
- d) 60 minutes.
Show Answer
Ans: d 60 minutes
We know that Speed is inversely proportional to time While he walks 25% slower means walk drove at 34(S) We know that D = S x T
When speed became 34(S) then Time taken should be 43(T) i.e, he walks taken 43(T) – T extra to cover the distance.
Extra Time = T3 = 20 min (as 20 min late due to slow driving) Actual time T = 60 Minutes
2. How many positive integers less than 500 can be formed using the numbers 1,2,3, and 5 for digits, each digit is used only once?
- a) 31
- b) 32
- c) 34
- d) 35
Show Answer
Ans: c 34
Single digit numbers = 4 Double digit numbers = 4 x 3 = 12
Three digit numbers = 3 x 3 x 2 x 1 = 18
Total = 34
3. In a people survey in the town of Bradford found that 50% of them prefer Milk. Another survey of 100 people in the town of Scottsdale found that 60% prefer Milk. In total 55% of all the people surveyed together prefer Milk. Find the total number of people surveyed?
Show Answer
Answer
50% (n) + 60% (100 ) = 55% (n + 100)
Solving we get n = 100
4. A Fruitwala sells a banana Rs.2 each but there were no sales at that price. But when he reduced the price all the banana were sold out enabling the fruitwala to realize Rs 164.90 from the banana alone , If the new price was not less than half the original price quoted How many banana were sold?
- a) 1.5 rs
- b) 1.7 rs
- c) 1.8 rs
- d) 1.9 rs
Show Answer
Answer: b) 1.7 rs
16490 = 2 × 5 × 17 × 97
Now the banana price should be greater than 1 and less than 2.
So 2 x 5 x 17 = 170
So Total banana sold = 97
and New banana price = Rs.1.7
5. What is the largest positive integer n for which 3^n divides 44^44?
Show Answer
Ans: n = 0
The digit sum of 4444 is when remainder obtained 4444 divided by 9
4444 = (45−1)44
Each term is a multiple of 9 but the last term which is (−1)44 = 1 So the digit sum of 4444 is 1.
Now the divisibility rule for 3, 9, 27… is the sum of the digits should be divisible by 3, 9, 27 respectively. In each case the digit sum is either multiple of 3 or 9.
So for any value of n > 1, the given expression is not divisible by 3n
6. The CP of an activa and a hunk is Rs 3 lakhs. The activa is sold at 20% profit and the hunk is sold at 10% loss. The overall gain is Rs 4200. What is the CP of the active?
- a) 100000 rs.
- b) 114000 rs.
- c) 120000 rs.
- d) 150000 rs.
Show Answer
Profit = 4200 Profit =SP – CP
4200=SP – 300000 therefore
SP=304200 x+y = 300000
1.2x + 0.9y = 304200
Solving for x = 114000 = CP of Activa
7. Gaurav and Monty can paint 720 windows in 20 days. Monty and Harish in 24 days and Harish and Gaurav in 15 days. Gaurav works for 4 days, Monty for 8 days, and Harish for 8 days. Find The total number of boxes painted by them?
- a) 220.
- b) 250.
- c) 300.
- d) 348.
Show Answer
Answer d 348
Capacity of G + M = 720 / 20 = 36 M + H = 720 / 24 = 30
H + G = 720 / 15 = 48
Combined capacity = 2 (G + H + M) = 114
G + H + M = 114 / 2 = 57
Now capacity of G = (G+H+M) – (H + M) = 57 – 30 = 27 M = (G+H+M) – (H + G) = 57 – 48 = 9
H = (G+H+M) – (G + M) = 57 – 36 = 21
Given that G worked for 4 days, and mark for 8 and harry for 8 days So total work by them = 4 x 27 + 8 x 9 + 8 x 21 = 348
8. The value of an artifact varies directly as the square of its weight. If a artifact f breaks into two pieces with weights in the ratio 2:3. what is the loss percentage in the value?
- a) 36%
- b) 40%
- c) 48%
- d) 50%
Show Answer
Answer:
Let weight be “x”
the cost of diamond in the original state is proportional to x2
when it is fallen it breaks into two pieces 2y and the 3y x = 5y
Original value of diamond = (5y)2 = 25y2
Value of diamond after breakage = (2y)2+(3y)2=13y2
so the percentage loss will be = 25y2−13y225y2×100=48%
9. Bushan alone can do a piece of work in 10 days. Anup alone can do it in 15 days. If the total wages for the work is Rs 5000, how much should Bushan be paid if they work together for the entire duration of the work?
- a) 2000
- b) 3000
- c) 4000
- d) 5000
Show Answer
Answer b 3000
Time taken by Anup and Bushan is in the ratio of = 3:2
Ratio of the Work = 2 : 3 (since, time and work are inversely proportional) Total money is divided in the ratio of 2 : 3 and Bushan gets Rs.3000
10. On a 24 question test, 1 point was deducted for each wrong answer, and 3 points were added for the right answers. if the score was zero. and all the questions were answered, Find how many were correct?
- a) 4
- b) 6
- c) 8
- d) 10
Show Answer
Let x questions were correct.
Therefore, (24- x) were wrong
3x−1(24−x)=0
Solving we get x=6
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